300

300

= 300 

Bài 2:

a. $=62-81-12+59-9=(62-12)+(59-9)-81$

$=50+50-81=100-81=19$

b. $=39+13-26-62-39=(39-39)+13-(26+62)$

$=0+13-88=-(88-13)=-75$

c. $=(32-42)+(36-34)+(40-38)=10+2+2=14$
d. $=92-55+8-45=(92+8)-(55+45)=100-100=0$

Bài 1:

a. $=(387-87)-224=300-224=76$

b. $=-(75+35)+379=-110+379=379-110=269$

c. $=(11+15)-(13+17)=25-30=-5$

d. $=(31-21)-(27-24)=10-3=7$

Bài 1:

1: =15+37+52-37-17=52-2=50

2: =38-42+14-25+27+15=62-42+29=20+29=49

Bài 1: Bỏ ngoặc rồi tính

3) (21-32) - (-12+32)=21-32-(-12)-32=21-32+12-32=-31

4) (12+21) - (23-21+10)=12+21-23+21-10=21

5) (57-725) - (605-53)=57-725-605+53=-1220

6) (55+45+15) - (15-55+45)=55+45+15-15+55-45=55+55=110

Bài 2: Tính các tổng sau một cách hợp lí

1) (-37) + 14 + 26 + 37=(-37+37)+(14+26)=0+40=40

2) (-24) +6 + 10 + 24=(-24+24)+(6+10)=0+16=16

3) 15 + 23 + (-25) + (-23)=(15-25)+(23-23)=-10+0=-10

4) 60 + 33 + (-50) + (-33)=(60-50)+(33-33)=10+0=10

5) (-16) + (-209) + (-14) + 209=(-16-14)+(-209+209)=-30+0=-30

6) (-12) + (-13) + 36 + (-11)=(-11-12-13)+36=-36+36=0

=15+37+52-37-17 =(37-37)+52+15-17 =0+52+15-17 =67-17 =50

(38 – 42 + 14) – (25 – 27 – 15) =38-42+14-25+27+15 =27 c. -(21 – 32) – (-12 + 32) =-21+32+12-32 =-9 d. -(12 + 21 – 23) - (23 – 21 + 10) =-12-21+23-23+21-10 =-22 e. (57 – 725) – (605 – 53) =57-725-605+53 =-1220 f. (55 + 45 + 15) – (15 – 55 + 45) =55+45+15-15+55-45 =110

A , 3 - ( 17 - x ) = 289 -  ( 36 + 289 )

3 - 17 + x = 0 - 36

-14 + x = -36

x = -36 - ( - 14 ) = -22

B, 25 - ( x + 5 ) = -415 - ( 15 - 415 )

25 - x - 5 = 0 - 15

20 - x = -15

x = 20 - ( - 15 ) = 35

C , 34 + ( 21 - x ) = ( 3747 - 30 ) - 3746

34 + 21 - x = 1 - 30 

55 - x = -29

x = 55 - (-29 ) = 74

D , -2x -  ( x -17 ) = 34 - ( -x + 25 )

- 2x - x + 17 = 34 - 25 + x

- 3x + 17 = 9 + x

- 3x - x = 9 - 17

-4x = -8

x = -8 : ( - 4 )

x = 2

E , 17x + ( -16x - 37 ) = x + 43

17x - 16x -37 = x + 43

x - 37 = x + 43

-37 - 43 = x - x 

- 80 = 0      ( vô lý )

G , ( x + 12 ) . (x - 3 ) = 0

\(\hept{\begin{cases}x+12=0\\x-3=0\end{cases}}\)

\(\hept{\begin{cases}x=-12\\x=3\end{cases}}\)

a. (21 - 1) x (21 - 2) x (21 - 3) x ... x (21 - 21)

= 20 x 19 x 18 x ... x 0

= 0

b. 3 x 27 x 8 + 4 x 35 x 6 + 2 x 38 x 12

= (3 x 8) x 27 + (4 x 6) x 35 + (2 x 12) x 38

= 24 x 27 + 24 x 35 + 24 x 38

= 24 x (27 + 35 + 38)

= 24 x100

= 2400

c. A = (1001 + 1002 + 1003 +... + 2009) x (360 x 87 - 360 x 32 - 360 x 55)

       = (1001 + 1002 + 1003 + ... + 2009) x [360 x (87 - 32 - 55)]

       = (1001 + 1002 + 1003 + ... + 2009) x (360 x 0)

       = (1001 + 1002 + 1003 + ... + 2009) x 0

        = 0 

Mình cảm ơn bạn nhiều :!!!

\(=\left(1^2+2^2+...+100^2\right)\cdot0=0\)